kernel_sanders
Joined 14 years ago
Joined 14 years ago
{1G}
Human Druid - Sage
{G}, Tap: Create 0/1 Plant Token named Seed of Knowledge
Sacrifice {X} Plants: Look at the top X cards of opponent's library
1/1
Since then, I lost the link and forgot the terms to search for it! I'm so glad you reposted it. =)
Edit: Wikipedia, of course, has a good overview of applications of Markov chains. http://en.wikipedia.org/wiki/Markov_chain#Applications
In a previous comment, I sought to further understand how the Lottery possesses the Markov property. Based on your definition above, I can see that it does simply because the distribution X_t of winning numbers has the same dependence on X_{t-1} as it does on X_1, ..., X_{t-1}, that is, zero. Do I have that correct?
I'm not seeing how the distribution of possible winning numbers relates at all to the current state. I'm trying to phrase this in the language of the above two comments. Help me out if I've got it all wrong. =)
Someone should conduct a real, independent poll an award a POY award from the Internets.