t0mek

I assume you're talking about the Atari 2600 console (VCS), which uses a limited version of that CPU, called 6507. It has the addressing space reduced to 16 KB.

This machine indeed has 128 bytes of RAM, but the code and data live on the cartridges, which can include up to 64 KB of ROM (exposing 4 KB at a time, with bank switching). Also, graphics is created on the fly ("racing the beam") at TV display, so there's no need to spend precious RAM on the framebuffer.

In comparison to the later constructions based on the 6502, like NES or C64, it was certainly not an easy platform to develop games, but not as hard as your comment is suggesting.

I used the "FX" option and I think there's a bug. The center tiles on each side always stay in the same position.

I like the "challenges" part at the end, especially the varying difficulty levels:

* A quadratic formula program, which outputs the number of roots and the x-intercepts upon the user inputting the values of A, B, and C.

* A fighting game, with health, a store, different enemies, weapons, armor, etc, with graphics and animation.

Only tangentially related (but hey, it's HN) - I'm so happy about the support/requirements for trailing commas in the modern language syntax:

    x = [
      123,
      456,
      789,
    ];

It makes editing such a list so much easier. Also, the commit diffs are cleaner (you don't need to add comma to the last element when appending a new one).

Famous example from the pop-culture is Burr vs Hamilton:

> If you stand for nothing, Burr, what'll you fall for?

The article doesn't mention the recent development in Amiga extension cards - PiStorm is an easy (and affordable) way to max out the specs of any Amiga, A600 included.

I've always seen A600 more like a budget version of A1200 rather than a new variant of A500: better graphics chip, IDE port, PCMCIA and new look-and-feel of the Workbench 2.04 (at the first sight hardly distinguishable from the Workbench 3.0) gave a taste of something new.

Yes, the liar have some hats. There are two ways how to conclude this:

1. If they don't have any hats, then any sentence about them would be truth.

2. The negation of the sentence, which must be truth, is "not all my hats are green". For this to be true, there must be some hats that are not green, so there must be some hats in general.

We can also assume that the p/q=√2 is already the simplest form of the fraction, since every fraction must have one, as in the first section of the article.

Then if we figure out that both p and q are even, it means that p/q can be simplified (by dividing p and q by 2), which contradicts the assumption about the simplest form - and we don't need to use the infinite descent.