ssp

In a figure-8 path where the intersection is in the center of a pixel, does Rasterizer set that pixel to 0.5 or to 0?

> If we assumed a radially symmetric kernel, then coverage would just be some monotonic function of the distance from the pixel center to the edge

I don't think that's true. Consider a simple case where the shape is a square and you are sampling in such a way that the closest edge point is closer to a corner of the square than the filter width. Using a function of distance you will get the same result as when sampling far from the corner. But the coverage is different in the two cases.

The equivalent in Oort produces:

    localhost:~/oort/examples% ../oort callcc2.nl 
    2
    1

as expected since Oort uses heap allocated activation records.

The Oort program:

    typedef continuation_t = fn (p: int32) -> void;
    
    call_cc (fun: fn(k: continuation_t) -> void) -> int32
    {
        retval: int32;
    
        fun (fn (v: int32) -> void {
            retval = v;
            goto current_continuation;
        });
        
        // If fun returns without calling the continuation,
        // then just return 0
        return 0;
    
    @current_continuation:
        return retval;
    }
    
    x: int32 = 0;
    
    print call_cc (fn (k: continuation_t) {
        x = 1;
        k (2);
        });
    
    print x;

Does copying the stack really work? What if some local variable changes in between the call/cc and calling the continuation? If the stack is a copy, that change will not be reflected when the continuation runs.

Do you have plans to make money off of this?