pksadiq

This specific change shall excite many as CC BY-SA 4.0 is one way GPLv3 compatible, but CC BY-SA 3.0 is not. Which means that free software developers can now embedded many Wikimedia contents in their GPLv3 applications. This seems not mentioned in the blog post though.

> since the decimal average is -0.5

The C standard says: When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded (This is often called ‘‘truncation toward zero’’).

So it should be 0 (as per C standard, not sure what C++ standard says)

> x/2 + y/2 + (x & y & 0x01)

This returns -1 for x = INT_MIN and y = INT_MAX were the answer should be 0 (for an example). so not a correct solution

  int mid(int x, int y) {
    return (x/2 + y/2) + (1 & x & y);
  }

would be a more readable solution

edit: Actually, this fails on mid(INT_MIN, INT_MAX) and possibly other mixed sign values (returns: -1, expected: 0 (or -1 is okay?), where the precise answer is -0.5)

more edit: The C standard says: When integers are divided, the result of the / operator is the algebraic quotient with any fractional part discarded (This is often called ‘‘truncation toward zero’’).

So -1/2 should be 0.