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Comment · 4 months ago
You are correct and this is another failing of the article. Hestenes has very little relevance to the field today - the Atiyah/Penrose school, via Jon Selig, is much more influential. To be fair the article would have been correct ten years ago, but not now (sorry Alex!)
Comment · 4 months ago
You're certainly correct that it would be the done thing in physics (and I have written a draft for my blog).

But note that Geometric Algebra is significantly a tool for graphics/game developers, who tend to prefer videos (even the older generation I think)

Comment · 4 months ago
Very sorry to hear about the brain fog, that's rough. Best of luck getting through it.

> in some cases

What cases do you have in mind?

> why are these your operators in the first place?

This is a perfectly reasonable question but I want to point out that it's a bit philosophical and not the kind of thing physics undergrads tend to enjoy hearing about. For example Clifford algebras like matrix algebras are associative algebras over commutative fields (real or complex numbers) - why? Why does the universe like that? I can hazard guesses but it's mostly above my paygrade, possibly above anyone's paygrade. But if it's to be asked of GA it should be asked of matrices too, I'm sure you can agree.

There's something that distinguishes Clifford algebras from matrix algebras. They start from the assumption that vectors anticommute when they're orthogonal. That's easy to explain. It says that if A and B are orthogonal vectors then A->B is the opposite (negation) of B->A.

Aside from those the last thing is that you say your basis vectors have a certain "metric" on them. There's deep philosophical questions about why the universe cares so much about metrics, but they're not at all specific to Clifford Algebra.

Personally I find that very intuitive, much more intuitive than any other tensor algebra I'm aware of.

Comment · 4 months ago
Ah! If you do it would probably would need to be a followup rather than addendum
Comment · 4 months ago
If you want to learn physics from a geometric viewpoint, GA is brilliant. Here's a playlist of my stuff, which is aimed at computer graphics folks: https://youtube.com/playlist?list=PL9a8DfUJQcuA9AXqvjxYolq5-...

Leading up to classical mechanics, you have the sibgraphi tutorials: https://youtube.com/playlist?list=PLsSPBzvBkYjxrsTOr0KLDilkZ... (I also recommend the bivector discord if you want a community)

And from there, sudgy's videos are good, and the tome "geometric algebra for physicists" packs in a huge amount of stuff.

Comment · 4 months ago
In physics and especially computer graphics, yes. These are two fields that are culturally very different from algebraic geometry, in that mathematical techniques that appear at all "exotic" are "hard to sell", even if they're useful. Hence having to have a more marketable name for Clifford algebra ("geometric algebra" is just Clifford algebra), and having to have endless screaming from the rooftops for people to learn the slightest thing (like "multiplication is transform composition").
Comment · 4 months ago
The geometric product is transform composition. It plays the same role as matrix multiplication: if a group is represented by a set of matrices or multivectors then the GP will be group composition.

For example Cl(4,2) can represent the spacetime conformal group and Cl(3,0,1) can represent the Euclidean group. If A and B are elements of those groups represented by multivectors then AB will be their composition.

That is an extremely fundamental operation. Almost as, if not more, fundamental than inner and wedge.

I mention this every time this article is posted on hacker news and nobody wants to talk about it :`(

Comment · 4 months ago
He's distressingly wrong about this, the geometric product is transform composition

(Apologies to folks who have seen me repeat this a million times; but it's very important folks be aware of it)

Comment · 4 months ago
Can do either! If your multivectors represent linear transformations then their products will also be linear transformations. If they're affine transformations then their products will be affine transformations. Euclidean, conformal, etc!
Comment · 4 months ago
The geometric product is transform composition.

TRANSFORM COMPOSITION!

(sorry, it's not your fault or even his that you didn't know this - GA textbooks should have it as the first thing they teach but they don't)

Comment · 4 months ago
I'm a GA researcher. I did this livestream of my reaction to the article

https://m.twitch.tv/videos/2282548167

TLDR it is quite a bad article. One of the closest thing he has to a real argument is "I don't like it when geometric objects are identified with operators, I want those to be separate things". But this is both anti-GA and anti-Lie-Theory. As he says, he is critical of mathematics as conventionally practiced. So be warned that if you find yourself disliking GA for anything like the reasons he dislikes GA, there's a lot of other (mainstream/prestigious) fields you dislike too.

Comment · 1 year ago
Since Geometric Algebra == Clifford Algebra, Michael Atiyah, Roger Penrose, and Paul Dirac disagree with you.
Comment · 1 year ago
Comment · 1 year ago
The geometric product does transform composition. It has all the properties you want for multiplication in an algebra, or indeed a monoid or group.

So it is like matrix multiplication, but for transforms represented as multivectors. Multivectors are nicer than matrices because they are made out of the separate (exterior algebra) objects so you can geometrically interpret them. For example, a rotation-reflection (rotoreflection/improper rotation) will have a grade 1 part and a grade 3 part. One of them is the plane you reflect in, one is the point you rotate around.

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