delamon
Joined 1 year ago
Joined 1 year ago
prev. submission - https://news.ycombinator.com/item?id=39529775
Yes, I was and still running go and zig binaries with mlockall. Apps have large in-application caches and also perform large streaming reads of datasets bigger than available RAM. If it happens that several streaming reads running at same time, they push memory pressure hard enough, so kernel swaps out cold parts of in-app caches. That later leads to elevated latencies => mlockall to avoid that.
Code pages are paged in on demand: for any sufficiently large binary just some code pages will be mapped right after start. Given enough memory pressure, the active LRU will be shrunk often enough to push code pages out of the active LRU and then they are eventually evicted.
I'm not aware how it works in modern MGLRU, but I would assume similar ovservable behevior holds.
The good thing is that mlock/mlockall does not require elevated permissions. But it is bounded by the memlock rlimit, which you need to configure for the container. If you don't want paging/swapping, set it equal to the total memory you give to the container and call it a day.
I'm curious about the technical implications. Which ones do you have in mind?
To be honest, I don't quite see how mlock makes it complex. It's quite the opposite: it has very clear semantics and makes reasoning about system behavior simple. Disabling swap is the opposite: you're making a bet and hoping it works.
You are correct, that 90MB Go binary is not major memory consumer. But it doesn't matter what is the source of memory pressure. What matters is what kernel do under pressure. If you disable swap, then under memory pressure kernel can only pageout memory mapped files, no matter how small they are. And your code will be paged out.