concreteblock
Joined 5 years ago
Joined 5 years ago
I thought it was a good question and the wording was compelling enough.
And if the formula only holds for photons, why can we say that frequncy = constant * momentum for other particles?
Why is the fourier transform of position equal to momentum?
I.e why is position conjugate to momentum?
More generally, why would the fourier transform of an observable be another observable?
Author is talking about how our physical theories, such as QFT, currently have more predictive power than any theories we currently have about machine learning/deep learning.
(Author has a PhD in theoretical physics).
Based on the parts which I've read so far, a more accurate title would be 'Why some currently hot parts of AI not well understood, and some parts of Physics well understood?'
I think the original title is an ok approximation of this.
I couldn't resist bringing up the poker bankroll example because I think your in-game-poker example was poorly chosen. To me, it looked like you came up with a situation where the criterion obviously had no hope of being applicable and then used it to argue that the criterion is useless. E.g. I could find a whole list of things for which calculus is not applicable, but that would not be a good argument for 'calculus is useless'. The example I gave is at least closer to the assumptions of the Kelly Criterion.
I think the main thing I wanted to do was to correct the misconception that Kelly is only maximizing expected log utility, because it is a shame if someone (including other readers) thinks that the Kelly Criterion is just a fancy name we gave for the argmax of E f(S) where f happens to be the logarithm.
After all this, you (and other readers) might still conclude that the criterion is useless. But the set of justifications, and maybe the certainty, in that position, should change.