Comment Comment by concreteblock I may have missed this, but doesn't this just raise the question:Why is the fourier transform of position equal to momentum?I.e why is position conjugate to momentum?More generally, why would the fourier transform of an observable be another observable? parent concreteblock 5 years ago
Why is the fourier transform of position equal to momentum?
I.e why is position conjugate to momentum?
More generally, why would the fourier transform of an observable be another observable?