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Comment by ron_k

I understand what you’re saying, but I read that phrase in a different way.

Let’s say you have two ways of doing the same thing: both work, both are legit and neither introduce GC bugs. The only difference between the two is that one can be verified by the compiler while the other can’t, so you are stuck with solution no. 1 although both would work.

To phrase it differently: the code that gets verified by the compiler is safe, but is all safe code verifiable by the compiler?

I’m not implying that’s the case, but that’s what I feel the author is saying.

parent ron_k 2 months ago

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