Comment by cubefox

I believe there is a misunderstanding. The compiler can check untagged unions just as much as it can check tagged unions. I don't think there is any problem with "ambiguous narrowing", or "reliability". There is also no risk of "nullable everywhere": If the type of x is Foo|Null, the compiler forces you to write a null check before you can access x.bar(). If the type of x is Foo, x is not nullable. So you don't have to remember null checks (or checks for other types): the compiler will remember them. There is no difference to tagged unions in this regard.