Comment Comment by Y_Y * doesn't (have to) mean "pointer"!It works in simple cases, but I find the consistent thing to do is read it as "dereference". double volatile *(const immutable_pointer); // immutable_pointer is immutable, when you dereference it you'll get a volatile double parent Y_Y 2 years ago
It works in simple cases, but I find the consistent thing to do is read it as "dereference".