Not disagreeing with you but what's interesting is that C++ doesn't hide in this particular situation. Smart pointers implement operator-> and operator* but then ptr.foo() is still always the foo() method of the pointer type (and won't compile if it doesn't have it) - you need ptr->foo() or (*ptr).foo() to get the method of the pointed-to type.
It's one of the few places that C++ is more explicit than Rust. I wonder if there's a reason Rust went a different way? I'm mainly a C++ programmer so I'm genuinely curious.
It's one of the few places that C++ is more explicit than Rust. I wonder if there's a reason Rust went a different way? I'm mainly a C++ programmer so I'm genuinely curious.