zodiac
Joined 14 years ago
Joined 14 years ago
For e.g., imagine I'm trying to prove the theorem "x divides 6 => x != 5". Of course, one way would be to develop some general lemma about non-divisibility, but a different hacky way might be to say "if x divides 6 then x ∈ {1, 2, 3, 6}, split into 4 cases, check that x != 5 holds in all cases". That first step requires an algorithm to go from a given number to its list of divisors, not just an existence proof that such a finite list exists.
I don't think this is true? AIUI a developer can choose to operating using the "old business terms" even in the EU, in which case they don't have to pay the fee. https://developer.apple.com/support/core-technology-fee/ backs this up by stating that the CTF is an element of the "new business terms".
www.xuanji.li
[ my public key: https://keybase.io/xuanji; my proof: https://keybase.io/xuanji/sigs/YyOVzG7h-Ip1eEcZdfnsvWckOKvnM-6b09PfP3q-9Y0 ]
hi