mathduck

Joined 6 years ago

Karma

Submissions

Member since

Feb 16

Recent submissions

You are artificially constructing a very limited range (upper bound and lower bound) in which of course the likelihood of any digit being the first digit won't be equal. This is nothing new. This does not contradict what other commenters have said about uniform distribution. With large ranges, even if you exclude a power of 10 in the upper bound, it does not change the 11.11% chance of each digit being the first digit.

But let us accept your very limited range for a moment and go along with it. Then you say that the numbers in this range follow Benford's law. But clearly, it doesn't. None of the probabilities in this range obey the probabilities in Benford's law.

Someone needs to revert the dubious edit (https://en.wikipedia.org/w/index.php?title=Benford%27s_law&d...) you have made in Wikipedia.