kspiteri
Joined 15 years ago
Karma
22
Submissions
8
Member since
Apr 7
Joined 15 years ago
> (A constant amount is of course independent of N anyway!)
When using O notation, we're doing asymptotic analysis and n can be arbitrarily large. If you have an arbitrarily large pointer, you cannot store the pointer in a constant number of bits. If your pointer is 64-bits long, you're cannot handle n > 2^64. That is why I said you need O(log n) rather than O(1).