hakken306

In space, there is only direct sunlight. On Earth, you have to consider illumination from the whole sky.

On Earth, the sun's disc at noon appears yellow-ish due to being white minus some blue light scattered away by the atmosphere. But there is also the rest of the sky illuminating the ground, as you can still easily see in shadowed areas. That is blue light from the sky hemisphere.

It very approximately adds back up to white overall for something exposed to direct sun and the whole sky, depending on the sun's position in the sky.

Your intuition is right in this case. A 2kW oven is more than enough to heat small chicken up to temperature. The author lazily took the 165F temperature and put it into a blackbody calculator without converting the units. Anything but the metric system...

Assuming the chicken has a surface area A=1m^2 (corresponding to a perfectly spherical chicken of radius=25cm/diameter=50cm, a little bigger than usual) and is a perfect blackbody (just going to handwave this one).

with the incorrect temperature: A blackbody with T=165°C (438 K) and A=1m^2 radiates P=2090 W.

with the correct temperature: A blackbody with T=74°C (347 K) and A=1m^2 radiates P=824 W.

Also neglected is the incoming radiation from the ambient environment. Without this, the "power loss" is closer to measuring the chicken in deep interstellar space. from a room temperature environment: T=20°C (293 K) and A=1m^2 radiates P=419 W onto the chicken.

The net power loss of the cooling chicken on the kitchen counter is therefore something like 824-419 = 405W, rapidly decreasing as the temperature drops towards room temperature. e.g. at 50°C it's around 200W.