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Comment by dllthomas

Two points here regarding Haskell. First, a function with typeclass constraints is less polymorphic (in that it will operate on fewer types) than polymorphic function without typeclass constraints. Of course, [the fully polymorphic version is] also more limited in how it interacts with the corresponding values.

Second, parametric polymorphism in Haskell is statically resolved. You can have polymorphic functions, but any given container still contains a single type. You can still do dynamic polymorphism in Haskell (by storing a list of records of functions, rather than storing data directly) but it doesn't typically involve type classes.

parent dllthomas 12 years ago

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