Comment

Comment by justinsteele

Problem "Where2"

Fails: SELECT facid, name, membercost, monthlymaintenance FROM cd.facilities WHERE membercost > 0 AND (membercost / monthlymaintenance) < (1/50);

Succeeds: SELECT facid, name, membercost, monthlymaintenance, (membercost / monthlymaintenance) as a FROM cd.facilities WHERE membercost > 0 AND (membercost / monthlymaintenance) < (0.02);

parent justinsteele 13 years ago

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