Comment

Comment by bonzini

> for all n, BB(n) is trivially computable, since it is a single integer".

It is not computable, because for high enough n you can't prove that you got the right integer.

And also you can prove that if a sequence a_n is always larger than BB(n) for some n, that sequence a_n is also not computable.

parent bonzini 18 days ago

Discussion

Live from the official Hacker News API

A modern reader for Hacker News · SvelteKit + Skeleton