Comment Comment by bonzini > for all n, BB(n) is trivially computable, since it is a single integer".It is not computable, because for high enough n you can't prove that you got the right integer.And also you can prove that if a sequence a_n is always larger than BB(n) for some n, that sequence a_n is also not computable. parent bonzini 18 days ago
It is not computable, because for high enough n you can't prove that you got the right integer.
And also you can prove that if a sequence a_n is always larger than BB(n) for some n, that sequence a_n is also not computable.