Comment Comment by Arcuru > If anything, the extra material for the case would be the perimeter length times the perimeter wall width times the heightThat's what they did?Perimeter length = 2*335mm + 2*235mmWall height diff = 2mmWall width = 1mm(2*335 + 2*235) * 2mm * 1mm = 2,280 mm^3 parent Arcuru 7 months ago
That's what they did?
Perimeter length = 2*335mm + 2*235mm
Wall height diff = 2mm
Wall width = 1mm
(2*335 + 2*235) * 2mm * 1mm = 2,280 mm^3