This could be obviously done with much less code: Just add "if"s for all even number, and at the end just return "odd" if none of the evens matched. 50% less code!
Or even simpler: If it's 0, return "even". If not, do a recursive call to n-1, if that equals "even", return "odd", otherwise return "even".
But the best way is probably to just use a library. Yes, 500MB of additional dependencies, but then it's a one-liner.
Or even simpler: If it's 0, return "even". If not, do a recursive call to n-1, if that equals "even", return "odd", otherwise return "even".
But the best way is probably to just use a library. Yes, 500MB of additional dependencies, but then it's a one-liner.