Comment by sowhatquestion

This can be edited down to six lines with a simple trick: a Python string multiplied by True will return itself, and multiplied by False will return the empty string.

  for i in range(110):
      pr = ""
      pr += "Fizz" * (i%3 == 0)
      pr += "Buzz" * (i%5 == 0)
      pr += "Bazz" * (i%7 == 0)
      print (pr if pr else i)

I iterated over range(110) to show that it handles the "FizzBuzzBazz" case correctly.

EDIT: Or we could use lambdas as OP's Ruby code did; this might be more maintainable...

  cases = [
      lambda n: "Fizz" * (n%3 == 0),
      lambda n: "Buzz" * (n%5 == 0),
      lambda n: "Bazz" * (n%7 == 0) ]

  for i in range(110):
      pr = ""
      for case in cases:
          pr += case(i)
      print (pr if pr else i)

That's nine nonblank lines.