Comment by abainbridge

eg 4:

   int foo(char const *s) {
     if (s[0] == 'h' && s[1] == 'e' && s[2] == 'l' && s[3] == 'l')
        return 1;
     return 0;
   }

The outputs 4 cmp instructions here, even though I'd have thought 1 was sufficient. https://godbolt.org/z/hqMnbrnKe