Comment Comment by jkafjanvnfaf It's new because it makes no sense.There already is an implicit "branch" on every array access in C, it's called an access violation.Do they test for a segfault on every single array access in the code base? No? Then they don't really have 100% branch coverage, do they? parent jkafjanvnfaf 1 year ago
There already is an implicit "branch" on every array access in C, it's called an access violation.
Do they test for a segfault on every single array access in the code base? No? Then they don't really have 100% branch coverage, do they?