I haven't touched Perl in about ten years but your example is kind of insane. This is the one place Python is more annoying than Perl???
my $a = ["foo", 123, {"bar" => [[1,2,3], {"qux" => "quux"}]}];
$a->[2]{"bar"}[1]{"spam"} = "eggs";
use JSON;
print(encode_json($a))
That's the same as your example (minus the tuple type), but where Perl shines over Python (a lot) is you could have done the following:
use JSON;
my $a = [];
$a->[2]{"bar"}[1]{"spam"} = "eggs";
print(encode_json($a))
which would yield the json: [null,null,{"bar":[null,{"spam":"eggs"}]}]
To do this in Python is truly grim:
import json
from collections import defaultdict
# recursive defaultdict using lambda
datastructure = lambda: defaultdict(datastructure)
a = [None] * 3
a[2] = datastructure()
a[2]["bar"][1]["spam"] = "eggs"
print(json.dumps(a))
and thats doing it the unpythonic way, if you were to do this like the typical Python dev would accept in an MR for a large corp you would have written:
import json
from collections import defaultdict
def datastructure():
return defaultdict(datastructure)
a = []
# expand list to at least length 3
while len(a) < 3:
a.append(None)
a[2] = datastructure()
a[2]["bar"][1]["spam"] = "eggs"
print(json.dumps(a))
They would still hate you for defaultdict(datastructure) though. Because absolutely no one in Python realises its got that level of expressionism one of the few places it does.
To do this in Python is truly grim:
and thats doing it the unpythonic way, if you were to do this like the typical Python dev would accept in an MR for a large corp you would have written: They would still hate you for defaultdict(datastructure) though. Because absolutely no one in Python realises its got that level of expressionism one of the few places it does.