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Comment by gregorygoc

> For small values of N, log(N) is essentially a constant, <= 32, so we can just disregard it, making sorting simply O(N). For large values, even so-called linear algorithms (e.g. linear search) are actually O(N log(N)), as the storage requirements for a single element grow with log(N) (i.e. to store distinct N=2^32 elements, you need N log(N) = 2^32 * 32 bits, but to store N=2^64 elements, you need 2^64 * 64 bits).

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parent gregorygoc 1 year ago

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