Comment Comment by dataflow > a^(p-2) = a^(-1) mod pTangent, but curious: what made you write it like this? I've only ever seen it written as a^(p-1) = 1 mod p or a^p = a mod p Is that form somehow more useful in some cases? parent dataflow 1 year ago
Tangent, but curious: what made you write it like this? I've only ever seen it written as
or Is that form somehow more useful in some cases?