Comment by akubera

As others have said, Rust's ownership model prevents data races, as it can prove that references to mutable data can only be created if there are no other references to that data. Safe Rust also prevents use-after-free, double-free, and use-uninitialized errors. Does not prevent memory leaks or deadlocks.

It's easy to write code that deadlocks; make two shared pointers to the same mutex, then lock them both. This compiles without warnings:

    let mutex_a = Arc::new(Mutex::new(0_u32));
    let mutex_b = mutex_a.clone();
    
    let a = mutex_a.lock().unwrap();
    let b = mutex_b.lock().unwrap();
    println!("{}", *a + *b);