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Comment by yig

I think you may have misunderstood the proposal. Your 3rd party library example would have to write `pystd2025::HashMap<pystd2025::U8String, size_t> member;`. Isn't that stable?

From the post:

  The sample code above used the pystd namespace. It does not actually exist. Instead it is defined like this in the cpp file:

    #include <pystd2025.hpp> 
    namespace pystd = pystd2025;
parent yig 1 year ago

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