"also implies the existence of a Tbb state, with a bbud quark content, that should be stable except with regard to weak decays"
Can someone explain this to me?
Tcc(3875)+ can decay to a D0 and a D+, yes? And this is a strong decay?
I guess the reason Tbb doesn't have an equivalent strong decay to B mesons because of the sign difference -- that is, B0 and B+ would have anti-bs, not bs; and anti-B0 and anti-B+ would have negative charge?
And so the only major decay pathway is for the b itself to decay to a K+ (plus lepton noise), giving a temporary bu\s\u\d pentaquark, that then has uninhibited decays?
I guess what I'm asking is... is this the right way to think about this?
Can someone explain this to me?
Tcc(3875)+ can decay to a D0 and a D+, yes? And this is a strong decay?
I guess the reason Tbb doesn't have an equivalent strong decay to B mesons because of the sign difference -- that is, B0 and B+ would have anti-bs, not bs; and anti-B0 and anti-B+ would have negative charge?
And so the only major decay pathway is for the b itself to decay to a K+ (plus lepton noise), giving a temporary bu\s\u\d pentaquark, that then has uninhibited decays?
I guess what I'm asking is... is this the right way to think about this?