Can this be true? Does the calculator have any irrational number? What if I enter PI * 2? Infinite precision, wouldn't that mean running until your RAM is full? Or would it simply work, because no irrational number is calculated to infinite (as many as the device could) digits and is therefore finite and can easily be multiplied?
Or another even simpler case: If division is infinite precision, and I enter (2/3) * X, does the calculator internally work with fractions? Otherwise it would have infinite digits to compute.
Or another even simpler case: If division is infinite precision, and I enter (2/3) * X, does the calculator internally work with fractions? Otherwise it would have infinite digits to compute.