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Comment by rvbissell

Actually, no: that Tau-centric area formula you gave derives naturally from taking the integral. Your example actually fits the expectation you have from what you learned in Calculus I. You should _expect_ that 1/2 scaling to be there.

If it seems awkward to you, it's only because of a lifetime of seeing it done in terms of pi.

parent rvbissell 2 years ago

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