i don't think that's right. it's just 1/t. after all, after t time, one task must have made progress; since there are t tasks, the probability that i'm the task that made progress is just 1/t
the primary point of confusion, i think, is that getting interrupted does not mean that you are necessarily going to lose the cas
i don't think that's right. it's just 1/t. after all, after t time, one task must have made progress; since there are t tasks, the probability that i'm the task that made progress is just 1/t
the primary point of confusion, i think, is that getting interrupted does not mean that you are necessarily going to lose the cas