Comment

Comment by au8er

Would it be better to do

  sparse_val = sparse[i]
  return sparse_val < n && dense[sparse_val] == i
Regardless, we are treading in undefined territory, and the behaviour is not something that can be reliably be dependent upon
parent au8er 3 years ago

Discussion

Live from the official Hacker News API

A modern reader for Hacker News · SvelteKit + Skeleton