No, it will completely eliminate it, if the capacitor is large enough. If you're super paranoid you can do the maths and compute how much does it cut off at such frequency ranges. It's likely to be a ridiculous value. And one does not have an infinite amplitude resolution in any measurement device.
Also, you can just power the LED from a separate voltage regulator. Which is somewhat likely anyways, as the IC will probably want a lower voltage.
(Don't get me wrong, it's cool stuff, but there's also a very easy solution.)
Also, you can just power the LED from a separate voltage regulator. Which is somewhat likely anyways, as the IC will probably want a lower voltage.
(Don't get me wrong, it's cool stuff, but there's also a very easy solution.)