Comment Comment by tr352 > For example, in Bayesian logic: x AND y is xy, x OR y is x + y - xyNo it isn't. P(x AND y) = P(x)P(y) only in the special case where x and y are independent. Unlike fuzzy logic, probabilistic logic is not truth functional. parent tr352 3 years ago
No it isn't. P(x AND y) = P(x)P(y) only in the special case where x and y are independent. Unlike fuzzy logic, probabilistic logic is not truth functional.