Comment by broken8ball

Binary implies two. Both B-trees and BSTs exist in the universe of m-ary trees. A BST and a B-tree would be equivalent only if the branching factor of the B-tree was set to 2, but practically this is rarely the case with indexes, given that a higher branching factor is generally more favorable to lookup times (“block accesses”) since the hight of the B-tree is reduced as m increases.