Comment by nneonneo

Cute fact about __debug__: it is one of the only ways to get compile-time conditionals in Python. Performing a comparison with `if __debug__:` will output byte code for the ensuing statement if and only if the interpreter is in debug mode - notably, in `-O` mode, it will not even generate a load of __debug__ and a conditional jump, and acts as if the statement didn’t exist at all.