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Comment by sohkamyung

It does say this at the end of the article.

> Because of the probabilistic elements, their proof only works for large enough hypergraphs — those with more than a specific number of vertices. This approach is common in combinatorics, and mathematicians consider it a nearly complete proof since it only omits a finite number of hypergraphs.

parent sohkamyung 5 years ago

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