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Comment by asdkjh345fd

>It takes an input range

Which should have a type.

>and returns a type that iterates through that range

Which should have a type. The entire point is that this is a solved problem, there is no excuse to simply throw up our hands and say "screw documentation we'll just say this function is a mystery".

Functor f => (a -> b) -> f a -> f b

And please don't miss the point and tell me D doesn't have Functor. The entire point is that D has something, and it doesn't tell us what that something is. It should. Documentation is good.

parent asdkjh345fd 6 years ago

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