Comment Comment by noctilux Agree. I was confused by this at first but if the slope on lines without dividing by population is:(log y2 - log y1) / (x2 - x1)Then if we scale y2 and y1 both by c, which is 1 / population:(log( c * y2 ) - log( c * y1 )) / (x2 - x1) =(log c + log y2 - log c - log y1) / (x2 - x1) =(log y2 - log y1) / (x2 - x1)So scaling by population does not change the slope of the graphs, only the intercept. parent noctilux 6 years ago
(log y2 - log y1) / (x2 - x1)
Then if we scale y2 and y1 both by c, which is 1 / population:
(log( c * y2 ) - log( c * y1 )) / (x2 - x1) =
(log c + log y2 - log c - log y1) / (x2 - x1) =
(log y2 - log y1) / (x2 - x1)
So scaling by population does not change the slope of the graphs, only the intercept.