Comment Comment by fcesco If anyone wants to dig into the math, this is a non linear recurrence relation, with an external dependency, that is n_d+1 = f(a,n_d) n^(d+1)bad news: How this behaves will depend a lot on a (containment measures etc...)good news: If we can make a grow faster than an exponential, we can win parent fcesco 6 years ago
bad news: How this behaves will depend a lot on a (containment measures etc...)
good news: If we can make a grow faster than an exponential, we can win