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Comment by ziedaniel1

I think you misread slightly.

> All of these algorithms take constant time, i.e., time independent of the input coefficients for any particular (n, c).

This means that once you have chosen a particular n and c, the time no longer varies. However, if n and c vary, the running time is definitely allowed to vary also (as the formulas n(c + n) and (c + n)(log cn)^2+o(1) clearly do).

parent ziedaniel1 7 years ago

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