Comment by zackattack

multiples of 11 => you need to get the digits to sum to be odd => you need to find a number with a 2:1 ratio of even:odd digits {odd + odd = even, even + even = even, odd + even = odd, odd + even + even = odd [(odd + even)=odd + even = odd], etc.}.

so 209 is the first number with the appropriate 2:1 ratio (edited).