Comment Comment by qmalzp What if you replace it withp(x|y) = 1, p(x|!y) = 0, and time(y) < time(x)That rules out the rooster counter-example. If y is a boolean, I guess the only thing you can "do" to it is negate it. parent qmalzp 8 years ago
p(x|y) = 1, p(x|!y) = 0, and time(y) < time(x)
That rules out the rooster counter-example. If y is a boolean, I guess the only thing you can "do" to it is negate it.