Comment Comment by classics2 > A GPIO pin starts out as an input; in that state, you can’t call the function set_high. It is a compile time error!Which is throughly incorrect. Of course you can set the state of an output register that’s set to input, that state will just not appear on the pin. parent classics2 8 years ago
Which is throughly incorrect. Of course you can set the state of an output register that’s set to input, that state will just not appear on the pin.