Comment by asher

Given a = [1, 2, 3, 4, 5]:

    Ruby:    a.map{|i| i+1}.reject{|i| i%3 == 0}.map{|i| i*i}
    Python:  [i*i for i in filter(lambda i: i%3 != 0, [i+1 for i in a])]

Please ignore the fact that the whole operation can be simplified mathematically - nontrivial map-grep-map operations do occur.

I find the Ruby version clearer because it proceeds from left to right like a shell pipeline.