Comment by unusualcool

Exactly. Some programs are inherently ambiguous. In such cases, we cannot do much. - Example 1: `void f(){x * y;}` It's impossible to know whether that is a multiplication or pointer declaration. - Example 2: `void f(){x y = 0;}` We can only know that x is a scalar type (in C terminology), but it could be an int, int * , int * * , etc.