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Comment by lkowalcz

The encryption here is being done by "adding 20" / "multiplying by -0.5"?

Given this "encrypted" X , y dataset, I could easily find the unencrypted version... (even if I don't know 20 or -0.5, this still reveals so much of the structure that I don't believe it provides any real protection against anything except the most lazy attackers)

parent lkowalcz 10 years ago

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