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Comment by kctess5

The expected value of both strategies is to have 1 success, but they have different variance. The first strategy has variance of 0.99, and the second strategy has variance 0. The chance of n out of 100 hits with the first strategy is: binomial(100,n) x 0.01^n x 0.99^(100-n)

edit: asterisks as multiplication signs => italics

parent kctess5 10 years ago

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